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Va rog frumos!(Pt. scoala)

Va Rog FrumosPt Scoala class=

Răspuns :

VicentiuYT22
[tex](2x) {}^{2} = 2 {}^{2} \times {}^{2} = 4x {}^{2} [/tex]
[tex]( - 3x {}^{3} ) {}^{2} = ( - 3) {}^{2} \times (x3) {}^{2} = 9x {}^{6} [/tex]
(2√3y²)²= 4×3y⁴= 12y⁴
(-2/5x²y)²= (-2/5)²x(x²)²xY²=4/25x⁴y²
(3x)*(-2y) = (3x)*(-2y)=-6xy
(√2xy²)*(-√8x2y) =-2y²*2x²y=-4x²y³

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