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Pepeneverde2004
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Copiati si completati:
a) (........+3x)²=......+12xy+......;
b) (........-2a)²=......-16ab+.......;
c) (4x+........)²=.......+4xy........;
d) (3a-.......)²=.......-4ab+........;

Răspuns :

Needhelp112
a) (2y + 3x)^2 = 4y^2 + 12xy + 9x^2
b) (4b-2a)^2 = 16b^2 - 16ab + 4a^2
c) (4x + y/2)^2 = 16x^2 + 4xy + 1/4*y^2
d) (3a - 2/3*b)^2 = 9a^2 - 4ab + 4/9 * y^2
a) (......+3x)²=.......+12xy+.....
(2y+3x)²=4y²+12xy+9x²

b) (......-2a)²=......-16ab+.....
(4b -2a)²= 16b²-16ab+4a²

c) (4x+......)²=......+4xy+......
(4x+[tex]\frac{y}{2}[/tex])²=16x²+4xy+[tex]\frac{1}{4}[/tex]y²

d) (3a-......)²=........-4ab+......
(3a-[tex]\frac{2}{3}[/tex]b)²=9a²-4ab+[tex]\frac{4}{9}[/tex]b²

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