a)
[tex]\it \sqrt{75} = \sqrt{25\cdot3} = 5\sqrt3
\\ \\
\sqrt{27} = \sqrt{9\cdot3} =\ 3\sqrt3
\\ \\
\sqrt{12} = \sqrt{4\cdot3} = \ 2\sqrt3
\\ \\
\sqrt{48} = \sqrt{16\cdot3} = 4\sqrt3[/tex]
Expresia devine:
[tex]\it 4\sqrt3\cdot(10\sqrt3-3\sqrt3+6\sqrt3)-2\sqrt3\cdot4\sqrt3 = 4\sqrt3\cdot13\sqrt3-8\cdot3 = \\ \\ = 52\cdot3-8\cdot3=3(52-8) =3\cdot44=132.[/tex]
-------------------------------
Efectuăm înmulțirile și expresia devine:
[tex]\it 8\sqrt{225} -4\sqrt{81} +12\sqrt{36} -2\sqrt{144} = 8\cdot15-4\cdot9+12\cdot6-2\cdot12= \\ \\ =120-36+72-24=192-60=132\ .[/tex]
