[tex]\frac{1}{2}x-\frac{1}{3} = \frac{1}{3}x \\ \frac{1}{2}x - \frac{1}{3}x = \frac{1}{3} \\ \frac{1}{6}x = \frac{1}{3} \\ x = \frac{6}{3} = 2 \\
\frac{1}{2}[\frac{1}{2}(\frac{1}{2}x-1)-1]+1=\frac{5}{4} \\
\frac{1}{2}(\frac{1}{4}x - \frac{1}{2} - 1) + 1 = \frac{5}{4} \\
\frac{1}{8}x - \frac{1}{4} - \frac{1}{2} + 1 = \frac{5}{4} \\
\frac{1}{8}x = \frac{5}{4} - 1 + \frac{1}{2} + \frac{1}{4} \\
\frac{1}{8}x = 1 \\ x = 8[/tex]