1.
a) 51>18 => 2^51>2^18
b) 9>7 => 7^32<9^32
2.
(5^2)^ab<5^26
=> 2ab<26 => ab<13 => ab poate fi 10, 11, 12.
3.
(2^2)^32=2^64
(2^3)^24=2^72
(2^4)^25=2^100
=> 4^32<8^24<16^25
4.
72=2^3 • 3^2
96=2^5 • 3
5^72=(5^3)^24=125^24
3^96=(3^4)^24=81^24
=> 5^72>3^96
