3.
a)
2^3^2 :(2^3)^2=
=2^9 : 2^(3×2) (aici este 3×2 puterea)=
=2^9: 2^6=
=2^(9-6)=
=2^3=
=8
b)
(3^10+3^11+3^12):(3^9+3^10+3^11)=
dam fac tot comun numarul cu puterea cea mai mica =>
= 3^10 ×(1+3+3^2) : 3^9× (1+3+3^2)=
=3^10 ×(4+9) :3^9×(4+9)=
=3^10 ×13 :3^9 ×13=
=(3^10:3^9)×13=
=(3^10-9)×13=
=(3^1)×13=
=3×13=
=39
b)
(3^10+3^11+3^12):(3^9+3^10+3^11)=
scoatem parantezele
3^10:3^9 +3^11:3^10 +3^12:3^11=
=3^1 +3^1 +3^1=
=3+3+3=
=9
Cred ca ultima e corectă
