Răspuns :
c.E.
x+1>0...x>-1
rezolvare
(1/2)³=x+1
1/8=x+1
x=1/8-1
x=-7/8>-1
x=-7/8
verificare
log in baza (1/2) din (1/8)=3 adevarat pt ca (1/2)³=1/8, bine rezolvat
x+1>0...x>-1
rezolvare
(1/2)³=x+1
1/8=x+1
x=1/8-1
x=-7/8>-1
x=-7/8
verificare
log in baza (1/2) din (1/8)=3 adevarat pt ca (1/2)³=1/8, bine rezolvat