Răspuns :
3x²+2x=1⇔3x²+2x-1=0
Δ=2²-4*3*-1=4+12=16>0
x1=-2+√16/2=-2+4/2=2/2=1.
x2=-2-√16/2=-2-4/2=-6/2=-3.
x(-3,1)∈R.Bafta!
Δ=2²-4*3*-1=4+12=16>0
x1=-2+√16/2=-2+4/2=2/2=1.
x2=-2-√16/2=-2-4/2=-6/2=-3.
x(-3,1)∈R.Bafta!