Răspuns :
[tex]\it \text{ Aria triunghiului echilateral} = \dfrac{l^2 \sqrt{3} }{4} \\ \\ A = \dfrac{16^2 \sqrt{3} }{4} \\ \\ A = \dfrac{256 \sqrt{3} }{4} \\ \\ A = 64 \sqrt{3} \ cm^2 [/tex]
[tex]\it \mathcal{A}_{\triangle}=\dfrac{\ell^2\sqrt3}{4}=\dfrac{\ell\cdot\ell\sqrt3}{4`}=\dfrac{16\cdot16\sqrt3}{4} =4\cdot16\sqrt3=64\sqrt3 \ cm^2[/tex]