Notam numerele cu a, b si c
Ma = ( a + b + c ) : 3 = 25
a + b + c = 3 x 25 = 75
Ma = ( a + b) : 2 = 23,5
a + b = 2 x 23,5 = 47
a, b = numere consecutive
b > a cu 1
a + (a+1) = 47
2 x a = 47 - 1
a = 46 : 2
a = 23→ primul numar
b = 23 + 1 = 24 → al doilea numar
a + b + c = 75
23 + 24 + c = 75
47 + c = 75
c = 75 - 47
c = 28 → al treilea numar
Verific: Ma = ( 23 + 24 + 28) : 3 = 75 : 3 = 25
Raspuns: 23, 24, 28
