Răspuns :
[tex]\log_3{(x+2)}-\log_3{(x-4)}=1\\
C.E.\: \left \{ {{x+2\ \textgreater \ 0} \atop {x-4\ \textgreater \ 0}} \right. \\
\log_3{\frac{x+2}{x-4}}=1\\
\frac{x+2}{x-4}=3^1\\
x+2=3(x-4)\\
x+2=3x-12\\
-2x=-14\\
x=7\:verifica\:C.E.[/tex]