a)
x/2=y/4=z/3=k
x=2k
y=4k
z=3k
Pentru k=1 avem x=2, y=4, z=3
b)
(2•4-3•2)/3•2 = (8-6)/6 = 2/6 = 1/3
c)
(2+3) ______ 100%
4 _________ p
p=400/5=80%
d)
x/2 + y/4 + z/3 = 300
Numitor comun 12
6x+3y+4z=3600
x=2k
y=4k
z=3k
12k+12k+12k=3600
36k=3600
k=100
=> x=200, y=400, z=300