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a fost răspuns

Scrieti ecuatile rectiilor transformarilor indicate in schema ..
P→P2O5→H3PO4→K3PO4→Zn3(PO4)2→ZnCl2←Zn

Răspuns :

Alexbonheur
[tex] P_{4} + 5O_{2} =\ \textgreater \[tex] P_{2}O_{5}
P_{2}O_{5} + H_{2}O =\ \textgreater \ H_{3}PO_{4}[/tex] [/tex]
[tex]2H_{3}PO_{4}+3K_{2}CO_{3}=\ \textgreater \ K_{3}PO_{4}+3CO_{2} + H_{2}O[/tex]
[tex]2 K_{3}PO_{4}+ZnI_2=\ \textgreater \ Zn_3(PO_4)_3+6KI[/tex]
[tex]Zn_3(PO_4)_3+6HCl =\ \textgreater \ 3ZnCl_2 + 2 H_{3}PO_{4}[/tex]
[tex]Zn+2HCl=\ \textgreater \ ZnCl_2 + H_2[/tex]

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