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Mayra73
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Calculeaza .
.(1/a-2-2/a+2-a/4-a^2):4/a-2
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Răspuns :

Needhelp112
   [1/(a-2) - 2/(a+2) - a/(4-a^2)] : 4/(a-2) = 
= [1/(a-2) - 2/(a+2) + a/(a^2-4)] : 4/(a-2) =
= [(a+2)/(a-2)(a+2) - 2(a-2)/(a-2)(a+2) + a/(a-2)(a+2)] : 4/(a-2) = 
= (a+2-2a+4+a)/(a-2)(a+2) x (a-2)/4 = 
= 6/(a+2) x 1/4 =
= 3/2(a+2) = 
= 3/(2a+4)

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