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Deea617
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precizati intre care2nr. consecutive sunt situate fractiile:19supra3, 37supra7, 56supra11

Răspuns :

Alexandranechip34amj
[tex]\frac{19}{3}=6\frac{1}{3}\Leftrightarrow6 \leq \frac{19}{3} \leq 7\\\\\frac{37}{7}=5\frac{2}{7}\Leftrightarrow5 \leq \frac{37}{7} \leq 6\\\\ \frac{56}{11}=5\frac{1}{11}\Leftrightarrow5 \leq \frac{56}{11} \leq 6[/tex]

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