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Adriana2002
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100 puncte!!
scrieti sub forma de fractie algebrica ireductibila (Y-5)^2/3Y+18 : 3Y^2-75/Y^2-36
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Răspuns :

[tex] \frac{(y-5)^2}{3y+18} : \frac{3y^2-75}{y^2-36} [/tex]

=[tex] \frac{(y-5)^2}{3(y+6)} * \frac{(y-6)(y+6)}{3(y-5)(y+5)} [/tex]

=[tex]\frac{(y-5)(y-6)}{9(y+5)} = \frac{y^2-11y+30}{9y+45}[/tex] 


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