p=?%
V(H2) = ? L
Fe +2HCl => FeCl2 + H2
md HCl = C×ms/100 = 36,5×200/100 = 73g
n HCl = 73/36,5 = 2 moli
n Fe = 70/56 = 1,25 moli
n Fe exces = 0,25 moli
1 mol Fe......2 moli HCl
1 mol Fe...2 moli HCl
p = mp/mimp×100 = 56/70×100 = 80%
n Fe = nH2 = 1mol
V H2 = 1×22,4 = 22,4 L