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a fost răspuns

Introduce.ti factorii sub radical:
7radical2 si 3pe 2 radical 10

Răspuns :

Iakabcristina2
7rad2=rad(7^2 • 2)=rad98
3/2rad10=rad[(3/2)^2 • 10=rad(9/4 • 10)=rad(45/2)
Alitta
[tex] 7{\sqrt2}=\sqrt{7^2\cdot2}=\sqrt{98}\;;\\ \frac{3}{2\sqrt{10}}=\frac{3}{\sqrt{2^2\cdot10}}=\frac{3}{\sqrt{40}}\;; [/tex]

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