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AndrewMD
a fost răspuns

Rezolvati in R ecuatia
b)2x+(3-6x)=-17
e)2pe3(4x-1pe3)=1pe9

Răspuns :

LeoJoJo
b)
[tex]2x + (3 - 6x) = - 17[/tex]
[tex]2x - 6x + 3= - 17[/tex]
[tex] - 4x = - 17 - 3[/tex]
[tex] - 4x = - 20[/tex]
[tex]x = - 20 \div ( - 4)[/tex]
[tex]x = 5[/tex]

e)

[tex] \frac{2}{3} (4x - \frac{1}{3} ) = \frac{1}{9} [/tex]
[tex] \frac{2}{3} ( \frac{12x}{3} - \frac{1}{3} ) = \frac{1}{9} [/tex]
[tex] \frac{2}{3} \times \frac{12x - 1}{3} = \frac{1}{9} [/tex]
[tex] \frac{2(12x - 1)}{9} = \frac{1}{9} [/tex]
[tex] \frac{24x - 2}{9} = \frac{1}{9} [/tex]
[tex]24x - 2 = 1[/tex]
[tex]24x = 3[/tex]
[tex]x = \frac{1}{8} [/tex]




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