Răspuns :
79-primul termen
b÷3-al doilea termen (a)
al treilea termen (b)
79+b÷3+b=263 |-79
b÷3 + b = 184 | ×3
b+3b = 552
4b=552 | ÷4
b=138 => a=46
Sper ca ai inteles!
b÷3-al doilea termen (a)
al treilea termen (b)
79+b÷3+b=263 |-79
b÷3 + b = 184 | ×3
b+3b = 552
4b=552 | ÷4
b=138 => a=46
Sper ca ai inteles!
avem numerele:
I . = 79
II. = |__|
III. = |__|__|__|
----------------------------------
total = 79 + 4*|__| = 263 => 4*|__| = 263-79 =184
|__| = 184 : 4 = 46
R: I. =79 ; II. = 46 si III. = 46*3=138 .
I . = 79
II. = |__|
III. = |__|__|__|
----------------------------------
total = 79 + 4*|__| = 263 => 4*|__| = 263-79 =184
|__| = 184 : 4 = 46
R: I. =79 ; II. = 46 si III. = 46*3=138 .