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(4/5√3 -5/2√12+3/√300):√6/5 va rog, cat mai repede

Răspuns :

M4ThSk1LLz
notez radicalx:radical din x
(4radical3/15 - 5/4radical3 + 3/10radical3):6radical5=
=(4radical3/15 - 5radical3/12 + 3radical3/30):6radical5=
=(16radical3/60 - 25radical3/60 + 6radical3/60):6radical5=
=(-3radical3/60):6radical5=
=-radical3/20 x 1/6radical5=
=-radical3/100
Baftă!

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