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ordonati crescator 2la puterea45, 3la puterea27, 4l puterea18

Răspuns :


[tex] {2}^{45} = ( {2}^{5} )^{9} = {32}^{9} \\ \\ {3}^{27} = ( {3}^{3} ) ^{9} = {27}^{9} \\ \\ {4}^{18} =( {4}^{2} )^{9} = {16}^{9} \\ \\ {4}^{18} < {3}^{27} < {2}^{45} [/tex]

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