calculez moli amestec
pV=nRT
1x656= nx0,082x(273+527)--->n=10 kmol
ec.1 CH3-CH2-CH2-CH3----> 2H2 + CH2=CH-CH=CH2 ori a Kmoli
ec.2 CH2=CH-CH2-CH3---> H2 + CH2=CH-CH=CH2 ori b Kmoli
a+b=10
a/b= 3/2----> a= 6Kmol butan; b= 4Kmol1butena
a. n= 10Kmol butadiena daca randamentul este 100%
n= 10x80/100= > 8Kmol butadiena la randament mai mic
1xV= 8x0,082x(273+27)---->V=196,8 mcub
b. nH2=(2a+b)= 16kmol
n,butadiena= (a+b)= 10kmol
n,total= 26kmol
M,mediu= n.H2XM/n,total+ n,butadienaxM/N,TOTAL
16x2/26+ 10x54/26=22g/mol
d= M,mediu/M,aer= 22/29=........................calculeaza !!!!!.
