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Crazysmiledudip31sqz
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Sa se rezolve in R 4^x-1=1/8

Răspuns :

   
[tex]\displaystyle\\ 4^{x-1}= \frac{1}{8}\\\\ \Big(2^2\Big)^{x-1} = \frac{1}{2^3}\\\\ 2^{2(x-1)} = 2^{-3} \\\\ 2(x-1)=-3\\\\ 2x-2 = -3\\\\ 2x = -3 + 2\\\\ 2x = -1\\\\ x = \boxed{\bf - \frac{1}{2}} [/tex]



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