a + ( a + 1) + ( a + 2 ) + ( a + 3 ) + ( a +4) + ( a + 5) + (a + 6) = 511
7 × a = 511 - (1+2+3+4+5+6)
7 × a = 490
a = 490 : 7
a = 70 → primul numar
70 + 6 = 76 → cel mai mare
Verific: 70 + 71 + 72 + 73 + 74 + 75 + 76 = 511 → suma celor sapte numre consecutive
Raspuns: b) 76
