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D(x)=x^2+2x/x^2+4x+4

Răspuns :

EnglishzzBoi
D(x)=x^2+2x/x^2+4x+4 =

= x^2​​+2x​^1−2​​+4x+4

=x^2​​+2x​^−1​​+4x+4
[tex]D(x)=\dfrac{x^2+2x}{x^2+4x+4}\\ D(x)=\dfrac{x(x+2)}{(x+2)^2}\\ \boxed{D(x)=\dfrac{x}{x+2}},\forall x\in \mathbb{R}\backslash \{-2\}[/tex]

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