x) totalul de drum
a) prima zi=1/8(x)
r) restul de drum
b) a 2-a zi =3/5(r)
c) a 3-ia zi=130m
x) |___|___|___|___|___|___|___|___|=> 8/8=x
a) \----------------/=>3/8(x) prima zi
r) |___|___|___|___|___|=> 5/8(x)
b) \----------------/=> 3/5(5/8(x)) a 2-a zi
c) |___|___|=> ultimul rest (2/8(x))
\----------/=130m
130m:2=65m=1/8(x)
1/8(x)=65m.....=> x=65*8.....=>x=520m (totalul de drum)
3*65=195m in prima zi
520-195=325m restul de drum
325:5*3=65*3=195m a 2-a zi
325-195=130m ultima zi
195+195+130=520 m in total
