Răspuns :
notam nr cu a, a+1, a+2 (sunt consecutive, cresc cu 1 unitate)
a+ a+1 +a+2=39
a+a+a=39-1-2
3a=36
a=12
a+1=13
a+2=14
a+ a+1 +a+2=39
a+a+a=39-1-2
3a=36
a=12
a+1=13
a+2=14