[tex]\it \dfrac{(\sqrt3-1)^2+\sqrt{12}}{(\sqrt5-1)(\sqrt5+1)} +\left(\dfrac{1}{3}\right)^{-2}= \dfrac{3 - 2\sqrt3+1+2\sqrt3}{5-1} + \left[\left(\dfrac{1}{3}\right)^{-1}\right ]^2
\\\;\\ \\\;\\
= \dfrac{4}{4} +\left(\dfrac{3}{1}\right)^2 =1+9=10[/tex]
O fracție ridicată la puterea -1 se inversează.
