Răspuns :
1)
Fie n numarul :
n : 2/5 = n - 30
n × 5/2 = n - 30 |×2
5×n = 2×n - 60
5×n - 2×n = - 60
3×n = - 60
n = - 20
2)
Notam cu a = lungimea traseului
3a/5 + 40 = 160 |×5
3×a + 200 = 800
3×a = 800-200
3×a = 600
a = 600 : 3
a = 200 km (lungimea traseului)
Fie n numarul :
n : 2/5 = n - 30
n × 5/2 = n - 30 |×2
5×n = 2×n - 60
5×n - 2×n = - 60
3×n = - 60
n = - 20
2)
Notam cu a = lungimea traseului
3a/5 + 40 = 160 |×5
3×a + 200 = 800
3×a = 800-200
3×a = 600
a = 600 : 3
a = 200 km (lungimea traseului)
1. Fie ”x” numarul cautat.
x*2/5 = x- 30
x-x*2/5 = 30
5x-2x = 150
3x = 150
x=50 km
2. Fie ” x ” numarul cautat.
3/5x+40=160
3/5x=160-40
3/5x=120
x=120:3/5
x=120*5/3
x=200 km
x*2/5 = x- 30
x-x*2/5 = 30
5x-2x = 150
3x = 150
x=50 km
2. Fie ” x ” numarul cautat.
3/5x+40=160
3/5x=160-40
3/5x=120
x=120:3/5
x=120*5/3
x=200 km