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PopaDelia21
a fost răspuns

5,(6) - 4 1supra3,




13,(6) + 5,3 (3) - 14 7supra9,



5,(6) + 2 8supra9,


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Răspuns :

Didi12342
5,(6) - 4 1/3 =

= (56 - 5)/9 - (4×3+1)/3 =

= 51/9 - 13/3 =

= (51 - 3×13)/9 =

= (51 - 39)/9 =

= 12/9 =

= 1,(3) = 1 intreg 3/9

13,(6) + 5,3(3) - 14 7/9 =

= (136-13)/9 + (533-53)90 - (14×9+7)/9 =

= 123/9 + 480/90 - 133/9 =

= (1230 + 480 - 1330)/90 =

= 380/90 =

= 38/9 =

= 4,(2)

5,(6) + 2 8/9 =

= (56 - 5)/9 + (2×9+8)/9 =

= 51/9 + 26/9 =

= 77/9 =

= 8,(5) =

= 8 intregi 5/9
1)5,(6)-4intregi1/3=
(56-5)/9-(3×4+1)/3=
51/9-13/3=
17/3-13/3=
4/3=
1,(3)
2)13,(6)+5,(3)-14 intreg 7/9=
(136-13)/9+(53-5)/9-(9×14+7)/9=
(123+48-133)/9=
(171-133)/9=
38/9=
4,(2)
3)5,(6)+2intregi8/9=
(56-5)/9+26/9=
(51+26)/9=
77/9=8,(5)

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