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Calculeaza a,b.c, apoi sumele a+b,c+a,a+b+c , unde
a-=1/4+1/6+1/8
b=1/20+1/40+1/50
c=1/20+1/12+1/24

/= supra
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Răspuns :

Needhelp112
a = 1/4+1/6+1/8 = 6/24+4/24+3/24 = 13/24
b = 1/20+1/40+1/50 = 10/200+5/200+4/200 = 19/200
c = 1/20+1/12+1/24 = 6/120+10/120+5/120 = 21/120

a+b = 13/24+19/200 = (13x25)/600 + (19x3)/600 = 325/600+57/600 = 382/600 = 191/300
c+a = 21/120 + 13/24 = 21/120 + (13x5)/120 = 21/120+65/120 = 86/120 = 43/60
a+b+c = 13/24+19/200+21/120 = (13x25)/600+(19x3)/600+(21x5)/600 = 325/600+57/600+105/600= 487/600

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