Răspuns :
a+b=120 (1)
a/2-b/3=35 |*2 => a-2b/3=70 (2)
(1)-(2) => b+2b/3=50 => 5b/3=50 => b=30
1() => a=90
a/2-b/3=35 |*2 => a-2b/3=70 (2)
(1)-(2) => b+2b/3=50 => 5b/3=50 => b=30
1() => a=90
a + b = 120 ==> a = 120-b
a : 2 - b : 3 = 35 |×6
3×a - 2×b = 210
Inlocuim in ultima relatie pe a cu 120-b
3×(120-b) - 2×b = 210
360 - 3×b - 2×b = 210
3×b+2×b = 360 - 210
5×b = 150
b = 150 : 5
b = 30
a = 120 - 30 = 90
Verificare:
90 + 30 = 120
90 : 2 - 30 : 3 = 45 - 10 = 35
a : 2 - b : 3 = 35 |×6
3×a - 2×b = 210
Inlocuim in ultima relatie pe a cu 120-b
3×(120-b) - 2×b = 210
360 - 3×b - 2×b = 210
3×b+2×b = 360 - 210
5×b = 150
b = 150 : 5
b = 30
a = 120 - 30 = 90
Verificare:
90 + 30 = 120
90 : 2 - 30 : 3 = 45 - 10 = 35