Răspuns :
a+b+c=351 tone rosii
c=a*3
b=c*3
a=?b=?c=?
a+3a+9a=351
13a=351
a=351:13
a=27 tone de rosii in prima zi
c=a*3
c=27*3
c=81 tone de rosii a 2-a zi
b=c*3
b=81*3
b=243 tone de rosii a 3-ia zi
Total : 27+81+243=351 (tone de rosii).
Sper ca te-am ajutat ! :)
c=a*3
b=c*3
a=?b=?c=?
a+3a+9a=351
13a=351
a=351:13
a=27 tone de rosii in prima zi
c=a*3
c=27*3
c=81 tone de rosii a 2-a zi
b=c*3
b=81*3
b=243 tone de rosii a 3-ia zi
Total : 27+81+243=351 (tone de rosii).
Sper ca te-am ajutat ! :)
I=?
II=3 III
III= 3 I
I+II+III=351
I+3 (3I) + 3 I = 351
I+ 9 I + 3 I = 351
13 I = 351
I= 27 ( 27 de tone in prima zi)
III=3*27=81 ( 81 de tone in a treia zi)
II= 3*81= 243 ( 243 de tone in a doua zi)
I+II+III=351
27+243+81=351
351=351
II=3 III
III= 3 I
I+II+III=351
I+3 (3I) + 3 I = 351
I+ 9 I + 3 I = 351
13 I = 351
I= 27 ( 27 de tone in prima zi)
III=3*27=81 ( 81 de tone in a treia zi)
II= 3*81= 243 ( 243 de tone in a doua zi)
I+II+III=351
27+243+81=351
351=351