Răspuns :
[tex]4x^2-25=0\\
4x^2=25\\
x^2=\dfrac{25}{4} |\sqrt{}\\
|x|=\dfrac{5}{2}\\
S:x\in\left\{\pm\dfrac{5}{2}\right\}[/tex]
(4x)la a 2 a -25=0
16x la a 2a -25=0
16x la a 2a =25
16x=radical din 25 =5
x=5/16
16x la a 2a -25=0
16x la a 2a =25
16x=radical din 25 =5
x=5/16
