METODA ALGEBRICA:
a + b + c = 513
a = 3×b
c = (a-b) + 27 = (3×b-b) + 27 = 2×b+27
inlocuim in prima relatie in functie de b
3×b + b + 2×b + 27 = 513
6×b = 513 - 27
6×b = 486
b = 486 : 6
b = 81
a = 3×81 = 243
c = 2×81+27 = 243+27 = 270
Verificare:
243 + 81 + 270 = 594