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CiobanuAndraLăcră200
a fost răspuns

Calculati : ( 27 la puterea 10 + 2 × 9 la puterea 15 ) ÷ 81 la puterea 7

Răspuns :

[tex](27^{10}+2\cdot 9^{15}):81^7= ((3^3)^{10}+2\cdot(3^2)^{15}):(3^4)^7=\\ (3^{30}+2\cdot 3^{30}):3^{28}=3^{30}(1+2):3^{28}=3^{31}:3^{28}=3^3=\boxed{27}[/tex]
(27¹⁰+2×9¹⁵)÷81⁷=
[(3³)¹⁰+2×(3³)¹⁵]÷(3⁴)⁷=
(3³⁰+2×3³⁰)÷3²⁸=
3³⁰(1+2)÷3²⁸=
3³¹÷3²⁸=
3³=
27

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