2. a) 3-metil 1- pentena
b) 1. CH2=C(CH2-CH3)-CH2-C(CH3)2-CH2-CH-3
2. CH3-CH=C(CH3)-C(CH2-CH3)2-CH3
3. CH2=C(CH3)-CH3
Ce am scris in paranteza sunt radicalii pe care trebuie sa.i legi in jos sau in sus de carbonul respectiv (o data sau de doua ori daca dupa paranteza am pus 2)
3. A. a) CH3-CH2-CH=CH2 + Br2---->CH3- CH2-CH(Br)-CH2(Br)
CH3-CH2-CH=CH2 + HBr--->CH3-CH2-CH(Br)-CH3
b) CH2=C(CH3)-CH3 + Br2---->CH2(Br)-C(CH3,Br)-CH3
CH2=C(CH3)-CH3+ HBr---->CH3-C(CH3,Br)-CH3
c). CH3-CH=CH-CH3+Br2---->CH3-CH(Br)-CH(Br)-CH3
CH3-CH=CH-CH3 +HBr---->CH3-CH2-CH(Br)-CH3
B. a) CH3-C(CH3)=CH-CH3+HCl---->CH3-C(CH3, Cl)-CH2-CH3
b). CH3-C(CH3)=CH-CH3+Br2----->CH3-C(CH3,Br)-CH(Br)-CH3
c) CH3-C(CH3)=CH-CH3+H2O------>CH3-C(CH3,OH)-CH2-CH3
d). CH3-C(CH3)=CH-CH3 + HBr---->CH3-C(CH3,Br)-CH2-CH3
e). CH3-C(CH3)=CH-CH3 + [O] + H2O(KMnO4)-------> CH3-C(CH3,OH)-CH(OH)-CH3
4. a) A. b) F. c) A. d) A
5. a) Markovnikov, bogat in hidrogen
b) aditie (de hidrogen)
d) geometeica (cis/trans)
6. Pasul 1. Calculez formula bruta a hidrocarburii (pentru asta ttebuie sa impart procentele la masa atomica a atomilor de C si H si dupa impart rezultatele la numarul cel mai mic obtinut)
C: 85,72:12=7,14
H: 14,28:1=14,28
C: 7,14:7,14=1
H: 14,28:7,14=2
Deci formula bruta= (CH2)n
Pasul 2: calculez n. Stiu ca densitatea in rapirt cu hidrogenul e 35, deci aplic formula :dH2=M formula bruta/M H2 rezulta 35=14n/2 rezulta n=5
Deci hidrocarbura este propena: C5H10
Izomeri:
1. CH2=CH-CH2-CH2-CH3 ( 1-propena)
2. CH3-CH=CH-CH2-CH3 (2-pentena)
3. CH2=C(CH3)-CH2-CH3 (2-metil 1-butena)
4. CH3-C(CH3)=CH-CH3 (2-metil 2-butena)
5. CH3-CH(CH3)-CH=CH3 (3-metil,1 butena)
6. CH2=C(CH3)2-CH3 (2,2 dimetil propena)
