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Răspuns :

Danaradu70
se amplifica prima fractie cu (3-2V2)^2016

[(3+2V2)^2016*(3-2V2)^2016 +1 ]/(3-2V2)^2016 *(3-2V2)^2016

(3+2V2)(3-2V2)= [3^2- (2V2)^2]= 9- 2^2*2=9-8=1

asa ca [(3+2V2)^2016*(3-2V2)^2016= [(3+2V2)(3-2V2)]^2016= 1^2016=1

se inlocuieste si obtin
[(3+2V2)^2016*(3-2V2)^2016 +1 ]/(3-2V2)^2016 *(3-2V2)^2016= 
 
1+1=2 ( numitorul  3-2V2 se simplifica  )

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