Răspuns :
din prima 0*paranteza patrata o sa dea 0
1+5*(32:8+0)=
1+5*4
1+20
21
1+5*{4+0*[40+8*(40-36)]}=
1+5*[4+0*(40+8*4)]=
1+5*[4+0*(40+32)]=
1+5*(4+0*72)=
1+5*4=
1+20
21
1+5*(32:8+0)=
1+5*4
1+20
21
1+5*{4+0*[40+8*(40-36)]}=
1+5*[4+0*(40+8*4)]=
1+5*[4+0*(40+32)]=
1+5*(4+0*72)=
1+5*4=
1+20
21
in paranteza rotunda prima data rezolvi impartirile pe urma scaderea
1+5x{32:8+0x[40+8x(40-36)]}=
=1+5x[32:8+0x(40+8x4)]=
=1+5x[32:8+0x(40+32)]=
=1+5x(32:8+0x72)=
=1+5x(4+0)=
=1+5x4=
=1+20=
=21
1+5x{32:8+0x[40+8x(40-36)]}=
=1+5x[32:8+0x(40+8x4)]=
=1+5x[32:8+0x(40+32)]=
=1+5x(32:8+0x72)=
=1+5x(4+0)=
=1+5x4=
=1+20=
=21