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Nickuletz
a fost răspuns

Simplificati ecuatia X^2+4y+xy+4x:x^2+7x+12 Va rog mult am nevoie de ajutor

Răspuns :

[tex]x^2+4x+4y+xy=x(x+4)+y(4+x)=(x+4)(y+4)\\ x^2+7x+12=x^2+4x+3x+12=x(x+4)+3(x+4)=(x+3)(x4)\\ \dfrac{x^2+4x+4y+xy}{x^2+7x+12}=\dfrac{(x+4)(y+4)}{(x+3)(x+4)}=\dfrac{y+4}{x+3}[/tex]

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