CxH(2x+2)
omolog superior : C(x+1)H(2x+4)
14x+ 2 = 0,8055(14x+16)
14x + 2 = 11,277x + 12,888 x = 4 C4H10
b = CH4 d = C3H6 e = C2H6 f = C2H4
C3H6 + Br2 ⇒C3H6Br2
Δm = 8,4g = mC3H6 ⇒ nC3H6 = 8,4/42 = 0,2 moli = nBr2 Vs = 0,2/0,5 = 0,4 l
nCH2=CH2 ⇒ -(-CH2-CH2-)n-
28n = 42000 n = 1500
