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Alma12
a fost răspuns

daca a×b=0.(6) si a×c=1,(3) si a×d=0,1(2), calculati a×(b+c);a×(b+c+d); a×(b+c-d).

Răspuns :

Iakabcristina2
0,(6)=6/9=2/3
1,(3)=1 intreg 3/9=4/3
0,1(2)=(12-1)/90=11/90
a×b+a×c=a×(b+c)=2/3 + 4/3 = 6/3 = 2
a×b+a×c+a×d=a×(b+c+d)=2 + 11/90 =191/90
a×b+a×c-a×d=a×(b+c-d)=2 - 11/90 =169/90

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