👤
a fost răspuns

2x+3/xla a 2-1+3x+2/xla a 2-1

Răspuns :

[tex]\dfrac{2x+3}{x^2-1}+\dfrac{3x+2}{x^2-1}=\dfrac{2x+3+3x+2}{x^2-1}=\dfrac{5x+5}{(x-1)(x+1)}=\\ \dfrac{5(x+1)}{(x-1)(x+1)}=\dfrac{5}{x-1},\forall x\in \mathbb{R}-\{\pm 1\}[/tex]

Alte intrebari