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a fost răspuns

[(2x+1)*10-6x]*3+2[7x+4(4-x)]=2x+138

Răspuns :

Pitic107
[(2x+1)×10-6x]×3+2 [7x+4 (4-x)]=2x+138
(20x+10-6x)×3+2 (7x+16-4x)=2x+138
(14x+10)×3+2 (3x+16)=2x+138
42x+30+6x+32=2x+138
48x+62=2x+138
48x-2x=138-62
46x=76
x=76÷46
x= 1,65