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Greeneyescurlyhair
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[tex]( \sqrt[3]{2}) ^x \ \textgreater \ \frac{1}{8} [/tex]

Răspuns :

[tex]( \sqrt[3]{2} )^x \ \textgreater \ \frac{1}{8} [/tex]
[tex] 2^{ \frac{1}{3}x } \ \textgreater \ 2^{-3} [/tex]
[tex] folosind a^x\ \textgreater \ a^y [/tex]
[tex] \frac{1}{3}x \ \textgreater \ -3 [/tex]
[tex]x \ \textgreater \ -9[/tex]

deci folosesti a^x > a^y si a > 1 si x>y

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