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Irinac123
a fost răspuns

scrieti cit mai simplu:a)2√50-3√32+1\3√1800;

b)4√18-2√8-√3(3√12-1);

c)|6-√37|+|7-√37|-3;

d) 5√(1-√3)la puterea 2 -√72

Răspuns :

Cocirmariadenis
a)2√50-3√32+1\3√1800=
=2·5√2-3·4√2+(1/3)x3x10√2=
=10√2-12√2+10√2=
=8√2

b)4√18-2√8-√3(3√12-1)=
=4×3√2-2×2√2-3√36+√3=
=12√2-4√2-3×6+√3=
=8√2-18+√3

c)  |6-√37|+|7-√37|-3=
=6-√37+7-√37-3=13-3-2√37=       
=10-2√37=
=2(5-√37)

d) 5√(1-√3)l² -√72=
=5×(1-√3-√9×√8=
=5-5√3-3×2√2=
=5-5√3-6√2=
=5-5√3-5√2-√2
=5(1-√3-√2)-√2