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Cristinadeea12342
a fost răspuns

Calculeaza:
a)5 la puterea 140:25 la puterea 70+8 la puterea 32:16 la puterea 24+100 la puterea 26:10 la puterea 48-2 la puterea 5×5 la puterea 2.
b)[3 la puterea 100:3 la puterea 10+(9 la puterea 5×3 la puterea 14)la puterea 5 :27 la puterea 10+(4 la puterea 30:4 la puterea 29-1 la puterea 70)la puterea 102:81 la puterea 3]:(2 la puterea 10:2 la puterea 9+2 la puterea 0)la puterea 90.
URGENT!!!DAU COROANA!!!REZOLVARE COMPLETĂ.

Răspuns :

Renatemambouko
a)5^140:25^70+8^32:16^24+100^26:10^48-2^5×5^2=
=5^140:5^140+2^96:2^96+10^52:10^48-32×25=
=1+1+10^4-800=
=1000-798=202

b)[3^100:3^10+(9^5×3^14)^5 :27^10+(4^30:4^29-1^70)^102:81^3]:
:(2^10:2^9+2^0)^90=
=[3^90+(3^10×3^14)^5 :3^30+(4^1-1)^102:3^12]:(2^1+1)^90=
=[3^90+(3^24)^5 :3^30+3^102:3^12]:3^90=
=(3^90+3^120:3^30+3^90):3^90=
=(3^90+3^90+3^90):3^90=
=1+1+1=3



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