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se cere compozitia procentuala a 2 moli de NaOH in 10 moli de apa?

Răspuns :

Tony00771
Masa NaOH=40g/mol
=>1 mol NaOH.....40g
2 moli NaOH.....x
x=80g

Masa H2O=18g/mol
=>1mol H2O.....18g
10 moli H2O....y
=>y=180g

=>c=md/ms*100=mNaOH/mH2O*100=44.44%

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