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Calculează: a) 10×[64×11-12+(44:4+30÷5)×2+132÷4]-25×4=?
b)(24÷3+15×2+9÷3+3)÷[72÷4+6×12)-15×4-8]=?Va roggg

Răspuns :

a) 10x[64×11+(11+6)×2+33]--100=
10×(704-12+17×2+33)-100
10×(692-34+33)-100
10×(658+33)-100
10×691-100
6910-100=6810
Cocirmariadenis
a) 
10×[64×11-12+(44:4+30÷5)×2+132÷4]-25×4=
=10x[704-12+(11+6)x2+33]-100=
=10x(692+17x2+33)-100=
=10x(692+34+33)-100=
=10x759-100=
=7590-100=
=7490

b)
(24÷3+15×2+9÷3+3)÷[72÷4+6×12)-15×4-8]=
=(8+30+3+3):[(18+72)-60-8]=
=44:(90-60-8)=
=44:22=
=2

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